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Use redhat as namespace for hummingbird rpms (#4615)
The namespace value of `redhat` signifies this as an RPM package produced and distributed by Red Hat. Signed-off-by: Scott Hebert <scoheb@gmail.com>
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@ -84,13 +84,13 @@ func newMetadataFromManifestLine(entry string) (*pkg.RpmDBEntry, error) {
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}, nil
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}
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// packageURL returns the PURL for the specific RHEL package (see https://github.com/package-url/purl-spec)
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// packageURL returns the PURL for the specific RHEL or Hummingbird package (see https://github.com/package-url/purl-spec)
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func packageURL(name, arch string, epoch *int, srpm string, version, release string, distro *linux.Release) string {
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var namespace string
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if distro != nil {
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namespace = distro.ID
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}
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if namespace == "rhel" {
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if namespace == "rhel" || namespace == "hummingbird" {
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namespace = "redhat"
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}
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if strings.HasPrefix(namespace, "opensuse") {
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@ -55,6 +55,20 @@ func Test_packageURL(t *testing.T) {
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},
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expected: "pkg:rpm/p@v-r",
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},
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{
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name: "hummingbird distro maps to redhat namespace",
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distro: &linux.Release{
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ID: "hummingbird",
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VersionID: "1.0",
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},
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metadata: pkg.RpmDBEntry{
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Name: "p",
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Version: "v",
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Release: "r",
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Epoch: nil,
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},
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expected: "pkg:rpm/redhat/p@v-r?distro=hummingbird-1.0",
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},
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{
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name: "with upstream source rpm info",
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distro: &linux.Release{
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